Question

A piece of solid weighs 120 g in air, 80 g in
water and 60 g in a liquid. The relative density
of the solid and that of the liquid are
respectively

a) 3,2
b) 2,3÷4
c) 3÷2,2
d) 4,3
​

Answer 1

Answer:

Given:

weight of solid in air = 120g

weight ofsolid in water = 80g

weight of solid in liquid = 60g

The relative density of an object is equal to the ratio of it's weight in air and the difference of it's weight in air and it's weight when the object is submerged in liquid.

For relative density of solid= 120g/(120g-80g)

=120/40= 3

Now, relative density of liquid can be calculated a the ratio of loss of weight of solid in liquid to the loss of weight in water.

e.g., relative density of liquid= (120-60)/(120-80)

=60/40

=1.5