a piece of steel has a volume 12cm3 and a mass of 96g.(a) g/km3 (b) kg/m3.
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Answered by
2
Answer:
Explanation:
Given :-
Volume of steel piece, V = 12³ cm = 12 × 10⁻⁶
Mass of steel piece, m = 96 g = 96 × 10⁻³
To Find :-
Density of steel piece = ?
Formula to be used :-
Density, D = Mass/Volume
Solution :-
Density = Mass/Volume
Density = 96 × 10⁻³ / 12 × 10⁻⁶
Density = 8 × 10³ kg/m³
Hence, the density of steel piece is 8 × 10³ kg/m³
Answered by
0
Answer:
Explanation:
Here,
Volume of iron, v = 12 cm³
Mass of iron, m = 96 g = 96/1000 kg = 0.096kg
And, we have to find,
Density of iron, d = ?
We know, by formula, that
Putting the values,
Hence, density of Iron is 0.008 kg/m³.
That's your answer.
Hope it'll help.. :-D
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