Question

a piece of steel has a volume of 12 cm 3 and mass of 96 g. what is its density in kg m-3 ?

Answer 1

Answer:

Step-by-step explanation:

Given :-

Volume of steel piece, V = 12³ cm = 12 × 10⁻⁶

Mass of steel piece, m = 96 g = 96 × 10⁻³

To Find :-

Density  of steel piece = ?

Formula to be used :-

Density, D = Mass/Volume

Solution :-

Density = Mass/Volume

Density = 96 × 10⁻³ / 12 × 10⁻⁶

Density  = 8 × 10³ kg/m³

Hence, the density  of steel piece is 8 × 10³ kg/m³

Answer 2

Answer :-

P = 8× 10³ kg/m³

Given :-

V = 12 cm³

m = 96 g

To find :-

The density in kg /m³

Solution:-

Density :- It is defined as the ratio of the mass and volume of a substance is known as it's density.

From definition:-

$\huge \boxed {P = \dfrac{M}{V}}$

First convert it in to SI unit .

1,000,000 cm³ = 1 m³

12 cm³ = 1.2 × 10^-5m³

1000 g = 1 kg

96 g = 0.096 kg

→$P = \dfrac{9.6 \times 10^{-2}}{1.2 \times 10^{-5}}$

→$P = 8 \times 10^{-2-(-5)}$

→$P = 8 \times 10^{-2+5}$

→$P = 8 \times 10^3$

→$P = 8000 kg /m^3$

hence,

The density of steel will be 8× 10³ kg/m³.