Question

a piece of steel has a volume of 12cm cube,and a mass of 96g.what is its density in kg/mcube

Answer 1

Here,
Volume of iron, v = 12 cm³
Mass of iron, m = 96 g = 96/1000 kg = 0.096kg

And, we have to find,
Density of iron, d = ?

We know, by formula, that

$d = \frac{m}{v}$
Putting the values,

$= > d = \frac{0.096}{12}$
$= > d = \frac{96}{12 \times 1000}$
$= > d = \frac{0.096}{12000}$
$= > d = 0.008$
Hence, density of Iron is 0.008 kg/m³.
That's your answer.

Hope it'll help.. :-D

Answer 2

1 m3 = 1000000 cm3

=> 1 cm3 = 1/1000000 m3

12cm^3 changes to 12/1000000 m3