Question

a piece of stone is thrown up it reaches max height in 10 sec . what is the initial speed with which it is thrown.
full explanation pls ​

Answer 1

Answer:

98m/s

Explanation:

v = u + at

v = 0 a =-9.8m/s2 ; t = 10s

0 = u + (-9.8)10

u = 98m/s

Answer 2

Answer:

Explanation:v=u+at

v=0 a=-9.8 t=10

0=u+(-9.8)*10

0=u - 98

u=98ms^-1

As the stone reaches Max height final vel will be zero. As the object 'S direction is opposite to that of gravity 's g will be negative