Question

a piece of stone is thrown vertically upward it reaches its maximum height in 3 seconds if the acceleration of the stone be 9.8 metre per second square directed towards the ground calculate the initial velocity of the stone with which it is thrown upward find the maximum height attained by it​

Answer 1

Answer:

t=u/g

u=gt=9.8*3=29.4m/s

Hmax=u^2/2g=44.1m

Answer 2

Answer:

hey buddy

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