a piece of stone is thrown vertically upwards. It reaches is the maximum height in 3 seconds. If the acceleration of stone be 9.8 M per second square directed towards the ground, calculate the initial velocity of the stone with which it is thrown upwards.
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HEYA DEAR!!!!!!!
HERE IS THE ANSWER TO YOUR QUESTION.......
At the max height the final velocity of stone becomes 0.
t=3 and a=-9.8
V=u+at
Substituting the values,
0=u-gt
U=gt
U=9.8×3
U=29.4m/s
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