Question

A piece of stone is thrown vertically upwards. It reaches its maximum height in 3seconds.If

the acceleration of the stone be 9.8m/s^2 directed towards the ground, calculate the initial

velocity of the stone with which it is thrown upwards. Find the maximum height attained by

it.​

Answer 1

Answer:

Initial velocity of the stone,

u=?

Final velocity of stone,

v=0 Acceleration due to gravity,

g= -9.8m/s2

Time, t=3 sec

Using relation, v=u + gt 0 = u -9.8 x 3 u

=29.4m/s

Answer 2

Answer:

Initial velocity of the stone,

u=?

Final velocity of stone,

v=0 Acceleration due to gravity,

g= -9.8m/s2

Time, t=3 sec

Using relation, v=u + gt 0 = u -9.8 x 3 u

=29.4m/s

hope it helps u !!