Question

A piece of stone is thrown vertically upwards. It reaches the maximum height in 3 seconds. If the acceleration of the stone be 9.8 m/s^2 directed towards the ground, calculate the initial velocity of the stone with which it is thrown upwards.​

Answer 1

Solution :-

Time to reach the max height ( T ) = 3 sec

Let The Initial Upward Velocity = u

As per formula, T = u / g

That means, u / g = 3

So, u = 3 × g

= 3 × 9.8

= 29.4 m/s

Answer 2

Refer to the Attachment.

Hope it Helps !!!!!