A piece of stone is thrown vertically upwards reaches the maximum height in 3 seconds if the acceleration of the sun is 9.8 metre per second square directed towards the ground calculate the initial velocity of the stone with which it is thrown upwards
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8
t=3sec
a=-9.8m/s sq.
v=0
u=
v=u+at
0=u +(-9.8*3)
0=u +(-29.4)
u=29.4m/s
a=-9.8m/s sq.
v=0
u=
v=u+at
0=u +(-9.8*3)
0=u +(-29.4)
u=29.4m/s
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