a piece of stone of mass 113 g sinks to the bottom in water contained in a measuring cylinder and water level is cylinder rises from 30 ml to 40 ml.Calculate relative density of stone.
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Answered by
133
Hey!
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Mass of stone = 113 g
Initial volume of cylinder = 30 ml
= 30 cm^3
Increased volume = 40 ml
= 40 cm^3
Volume = 40-30
= 10 cm^3
Density of stone = Mass/Volume
= 113/10
= 11.3 g/cm^3
Relative density = Density of object / Density of water at 4°C
R.D = 11.3/1
R.D = 11.3
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Hope it helps...!!!
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Mass of stone = 113 g
Initial volume of cylinder = 30 ml
= 30 cm^3
Increased volume = 40 ml
= 40 cm^3
Volume = 40-30
= 10 cm^3
Density of stone = Mass/Volume
= 113/10
= 11.3 g/cm^3
Relative density = Density of object / Density of water at 4°C
R.D = 11.3/1
R.D = 11.3
______________
Hope it helps...!!!
shelly22:
thnx so much
its my pleasure.
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21
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hey buddy
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