Question

a piece of stone of mass 15.1 g is first immersed in a liquid & it weighs 10.9 gf. then on immersing the piece of stone in water, it weighs 9.7 gf. calculate:

a)weight of piece of stone in air

b)volume of piece of stone

c)relative density of stone

d)relative density of liquid


(plzzzzzz do itttttt)

Answer 1

Explanation:

relative density of liquid = mass / volume = 4.2 / 5.4 = 0.78

Answer 2

Answer:

Weight in air = 15.1 gf

 

loss of weight of stone in water = 15.1-9.7 = 5.4gf

hence displaced volume of water = volume of stone = 5.4 cc

 

relative density of stone = mass/volume = 15.1/5.4 ≈ 2.8

 

loss of weight of stone in liquid = 15.1 - 10.9 = 4.2 gf

 

volume of displaced liquid = volume of displaced water = 5.4 c.c

weight of displaced liquid = loss of weight of stone in liquid = 4.2gf

 

relative density of liquid = mass/volume = 4.2/5.4 = 0.78

Explanation: