A piece of thin wire is in form of an equilateral triangle of side 31.4 decimetre is bent into a ring with no loss of wire. Find the diameter of the ring
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Perimeter of equalietral triangle = side x 3
31.4 x 3 = 94.2 dm
Now, 2 x 22/7 x r = 94.2
r = 94.2 ÷ 6.28
r = 15 dm
diameter = 15 x 2 = 30 decimeter
31.4 x 3 = 94.2 dm
Now, 2 x 22/7 x r = 94.2
r = 94.2 ÷ 6.28
r = 15 dm
diameter = 15 x 2 = 30 decimeter
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2
the answer is 15 m with example
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