Question

A piece of wire 144 cm long is bent form a semicircle ad shown in figure . Find the diameter of semicircle

Answer 1

Length of Piece of wire = 144 cm
It bents to form semicircle.
=> perimeter of semicircle= 144

But we know, perimeter of semicircle
$\frac{1}{2} \pi \times d + d$
=>144= 1/2*3.14*d+d
144=d(1.57+1)
144/2.57=d
56.03