Question

A piece of wire 20 cm long is bent into the form of an arc with angle 60 degree find its radius

Answer 1

Hiiiii


According to the question,

The perimeter of arc will be = 20cm

Angle substended at the centre of the circle = 60°

Therefore,
We will use the formula,

theta/360° × 2πr. = circumference of arc

So,

60°/360° × 2×22/7×r = 20

1/6 × 2 × 22/7 × r = 20

r = 11×7×6/44

r = 7×6/4

r = 7×3/2

r = 10.5cm

So, radius of circle is 10.5 cm

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Answer 2

Answer:

Step-by-step explanation:

It is given that the length of the wire is 20 cm.

When it is bent in the form of an arc, it forms a part of the circumference of an imaginary circle.

And the formula of the length of an arc is {(given angle)/360}* 2*pi*r

So by putting the values we get that

(60/360) *2*(22/7)*r = 20cm

r = (20*360*7)/(60*2*22)

r = 19.1 cm (approximately)