Question

a piece of wire 3/4 m long was cut into three pieces .the first piece was 3/20 m long , while the length of the second piece was 5/3 of the first piece how long was the third piece?

Answer 1

Here is ur answer .
hope it helps

Answer 2

Answer: The length of third piece is $\dfrac{7}{20}\ m$

Step-by-step explanation:

Since we have given that

Length of a piece of wire = $\dfrac{3}{4}\ m$

Length of first piece of wire = $\dfrac{3}{20}\ m$

Length of second piece of wire = $\dfrac{5}{3}\times \dfrac{3}{20}=\dfrac{1}{4}\ m$

Let the length of third piece of wire be x.

According to question, it becomes,

$\dfrac{3}{20}+\dfrac{1}{4}+x=\dfrac{3}{4}\\\\\\\dfrac{3+5}{20}x=\dfrac{3}{4}\\\\\\\dfrac{8}{20}+x=\dfrac{3}{4}\\\\\\x=\dfrac{3}{4}-\dfrac{8}{20}\\\\\\x=\dfrac{15-8}{20}\ m=\dfrac{7}{20}$

Hence, the length of third piece is $\dfrac{7}{20}\ m$