Question

A piece of wire 40 cm is bent to form a right-angled triangle whose hypotenuse is 17 cm long. find the lengths of the other two sides of the triangle

Answer 1

Answer:

hypotanus is 17

so 15ka squre

8ka squre

we sum both of them h^2=b^2+p^2

h^2=17*17=289

then we found 15ka squre and sum of 8ka squre

225+64=289 so

lenght =15,bredth =8