Question

A piece of wire 42 cm long is bent into the shape of a rectangle whose width is twice its length. Find the dimensions of the rectangle.

Answer 1

Total perimeter of 42cm

=> 2(l+b)= 42

l+b= 21

Given b=2l ,

3l = 21

l = 7cm

And b = 14cm

Answer 2

Length of wire = 42

Let the length be X

Then breadth is 2x

Perimeter of rectangle = 2(l + b)

2( x+ 2x ) = 42

x + 2x= 21

3x= 21

x = 7

Length= 7, Breadth = 14