Question

a piece of wire 44 cm long is cut into two parts and each part is bent to form a square. if the total area of the two squares is 63 m^2. find the perimeter of the two squares​

Answer 1

Answer:

26.5 cm and 17.5 cm

Step-by-step explanation:

Let the pieces of wire be x and y, these are perimeters of the squares

We have:

x+y=44 cm => y=44-x

The two squares have sides: x/4 and y/4

(x/4)^2+(y/4)^2=63 cm^2

x^2+y^2=63*16

x^2+(44-x)^2-1008=0

x^2+x^2-88x+44^2-1008=0

2x^2-88x+928=0

x^2-44x+464=0

Solving quadratic equation:

x=17.5 cm or x=26.5cm

y=26.5 cm or y= 17.5 cm

Hope it helps

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