Question

A piece of wire 44cm long is cut into two parts. Each part is bent to form a square. Given that the total area of the two squares is 65cm^2, find the perimeter of each square.​

Answer 1

Answer:

Perimeter of first square is 16 and that of second square is 28.

Step-by-step explanation:

let one of the parts have length equal to x cm.

area of that part will be = (x/4)(x/4) = $x^{2}$/16

area of other part will be = (11-x/4)(11-x/4) = 121-11x/2+$x^{2}$/16

both area = 65 = $x^{2}$/16+$x^{2}$/16+121-11x/2

x = 28, 16

perimeter of first square is 16 and that of second square is 28.