Question

A piece of wire 48m long is bent to form a rectangle whose length is twice its width. Find its area.

Answer 1

Answer:

128m²

Step-by-step explanation:

Hey There

Here is your answer step by step.

============================

Width = X

Length = 2X

length of wire = perimeter of rectangle

48m = 2(2X + X)

48m = 2 × 3X

48m = 6X

48m/6 = X

8m = X

X = 8m

So,

length = 2X = 2 × 8m = 16m

width = X = 8m

area = length × breadth

= 8m × 16m

= 128m²

============================

Hope it's helpful for you!