Question

A piece of wire having a resistance Risque
into five equal parts.
a) How will the resistance of each par
of the wire change compared with the
original resistance?
b) If the five parts of the wire are placed in
parallel, how will the resistance of the
combination change?
c) What will be ratio of the effective
resistance in series connection to that of
the parallel connection?
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Answer 1

Answer:

a. if you break a wire of R resistance in 5 equal parts then the resistance of each part will become R/5 ohm.

means it becomes one fifth of original resistance.

b. if these equal 5 parts of R/5 ohm are connected in parallel then effective resistance will become (resistance of one part) / (number of resistances to be connected in parallel )

therefore effective resistance

becomes = (R/5)/5

= R/25 ohms

c. if 5 resistances of R/5 ohms connected in series and in parallel then their ratio in series and parallel will become

series resistance =5(R/5) =R

parallel resistance = (R/5)/5 = R/25

therefore series /parallel = 25 or 5^2

Explanation: