Question

A piece of wire in the form of a rectangle 8.9cm long and 5.4cm broad is reshaped and bent into the form of a circle.

Answer 1

Answer:

Step-by-step explanation:

Perimeter of rectangle = 2(l+b)

                                    = 2( 8.9 + 5.4)

                                    = 2(14.3)

                                    = 28.6cm

P(rectangle) = P(circle)

28.6 = 2 x 22 x r/7

200.2 = 44r

r = 4.5cm

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Answer 2

The radius of the circle is 4.55 cm.

Step-by-step explanation:

Given : A piece of wire in the from of a rectangle 8.9 cm long and 5.4 cm broad is reshaped and bent into the from of a circle.

To Find : The radius of the circle ?

Solution :

A piece of wire in the from of a rectangle 8.9 cm long and 5.4 cm broad.

The perimeter of the rectangle is

$P=2(l+b)$

$P=2(8.9+5.4)$

$P=2(14.3)$

$P=28.6\ cm$

A piece of wire in the from of a rectangle is reshaped and bent into the from of a circle.

So, Perimeter of the rectangle = Circumference of circle

i.e. $28.6=2\pi r$

$28.6=2\times 3.14\times r$

$r=\frac{28.6}{2\times 3.14}$

$r=4.55$

Therefore, the radius of the circle is 4.55 cm.

#Learn more

A piece of wire is in the form of a rectangle with dimensions 26 cm and 18cm is reshaped and went into form a circle.find the radius​

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