Question

A piece of wire in the shape of a rectangle whose length and breadth are 25 cm and19 cm given is rebent in the form of a circle. Find the radius of the circle .
[ ANSWER 14 CM]​

Answer 1

Answer:

Perimeter of rectangle = 2( l + b )

= 2(25+19)

=88cm^2

Circumference of circle = perimeter of rectangle

2πr = 88

r = 44× 7/22

= 2 ×7

= 14 cm

Step-by-step explanation:

Answer 2

Answer :-

Radius of circle = 14 cm

Explanation :-

Length (l) = 25 cm

Breadth (b) = 19 cm

Since the wire is bent from rectangle into the form of a circle, so we have to compare the perimeter and circumference of the rectangle and circle respectively.

According to the question,

$2(l + b) = 2 \pi r \\ = > l + b = \pi r \\ = > 25 + 19 = \frac{22}{7} \times r \\ = > 44 = \frac{22}{7} \times r \\ = > r = \frac{44 \times 7}{22} \\ = > r = 2 \times 7 \\ = > r = 14 \: cm$

Hence, the radius of the circle is 14 cm.