Question

A piece of wire is 190 cm long. It is bent
to form an isosceles triangle with the
base measuring 75 cm. What is the
length of the other two equal sides?​

Answer 1

Answer:

Given :

$\textsf{Length of the wire = 190 cm}$

$\textsf{It bent to an isosceles triangle }$

$\textsf{Base of the triangle = 75 cm}$

To Find :

$\textsf{Lenght of two equal sides}$

Concept :

Let the rest two side be 2x

To find the the rest two sides use this equation -:

$\sf{\boxed{2x+75cm=190cm}}$

Solution :

$\sf{\implies{2x+75cm=190cm}}$

$\sf{\implies{2x=190cm-75cm}}$

$\sf{\implies{2x=105cm}}$

$\sf{\implies{x=\dfrac{\cancel{115cm}}{\cancel{2}}}}$

$\sf{\implies{x=57.5cm}}$

Verification :

To verify the answer just do sum of the length of all sides of the isosceles triangle . If the answer will come 190 cm . Then , the answer will be verified .

$\sf{\implies{75cm+57.5cm+57.5cm}}$

$\sf{\implies{132.5cm+57.5cm}}$

$\sf{\implies{190cm}}$

Hence , the answer is verified .

Answer :

So , the both equal sides of the isosceles triangle is 57.5 cm and 57.5 cm .

Answer 2

Step-by-step explanation:

Given:

Lenth of piece of wire of 190 cm long bent to form an isosceles triangle with base measuring 75 cm.

Therefore, Perimeter=190 cm.

Base=75 cm.

To find:

Length of other two sides

Concept used:

In an isosceles triangle ,there are two equal sides

and the perimeter is sum of all three sides.

Solution:

Let other two side of same length be x.

Now;

Perimeter= Sum of three sides

=>190=x+x+75

=>190=2x+75

=>190-75=2x

=>117=2x

=>x=105/2=52.5

Hence length of other two sides is 52.5 cm.