Question

A piece of wire is bent in shape of an equilateral triangle of each side being 7.2cms . It is rebent to form of circular ring. Find diameter of the ring ​

Answer 1

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Step-by-step explanation:

Answer 2

Answer:

$\huge\underline{ \underline{ \purple{your \: \: \: answer\:6.87cm}}}$

Step-by-step explanation:

$\bf\red{peremeter \: of \: triangle = circumference \: of \: circle} \\ \\ \bf\ \hookrightarrow3side = \pi \: d \\ \\ \bf\hookrightarrow3 \times 7.2cm = \frac{22}{7}d \\ \\ \bf\ \hookrightarrow21.6 = \frac{22d}{7} \\ \\ \bf\ \hookrightarrow22d =( 21.7 \times 7 )cm \\ \\ \bf\ \hookrightarrow \: 22d = 151.2cm \\ \\ \bf\ \hookrightarrow \: d = \frac{151.2}{22} \\ \\ \bf\boxed{ \hookrightarrow \: d = 6.87cm} \\ \\ \bf\ \large\underline {so \: the \: diameter \: of \: the \: rind \: is \: 6.87cm}$

$\large\boxed{ \fcolorbox{green}{red}{hope \: it \: help \: you}}$