Question

a piece of wire is bent in the for. of square encloser an area of 484 square cm if the same wires is bent to form a circle find the circumference and area that will enclose

Answer 1

a square =484
a =22

4a=total length of wire=88

2πr=circumference=length of wire=88

r=14
Area =πr.r
=616


With corresponding units

Answer 2

Perimeter of square of side $x$is $4x$ cm
So as you have given area of square $x^{2} = 484 = 22*22$
So side of square is 22 cm
So length of wire is $4x = 4*22 = 88 cm$
So circumference of circle is 88 cm
Circumference of circle of radius r is $2 \pi r$
so $2\pi r = 88$
take $\pi = \frac{22}{7} (approx)$
$r = \frac{88*7}{22 * 2} = 14 cm$
Area of circle of radius r is $\pi r^2$
so area of circle is $\frac{22}{7}* 14 * 14 = 616$