a piece of wire is bent in the form of an equilateral triangle each of the side is 66 MM this wire is bent to form a circular ring find the diameter of the Ring.
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Circumference of circle is 2(pi)r.
66 =2 *pi*r
66 *3 = 2*22/7*r
66*3*1/2*7/22 =r
31.5 =r
Diameter = 2r
= 2*31.5
=63mm
66 =2 *pi*r
66 *3 = 2*22/7*r
66*3*1/2*7/22 =r
31.5 =r
Diameter = 2r
= 2*31.5
=63mm
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