Question

A piece of wire is bent in the shape of a a rectangle whose length and width are 35 cm and 20 CM respectively .It is opened and Rebent to form a circular ring. What is the diameter of the Ring?​

Answer 1

Answer:

35

Step-by-step explanation:

The diameter of ring is 35 cm.

Step-by-step explanation:

We are given the following in the question:

Length of rectangle = 35 cm

Width of rectangle = 20 cm

Perimeter of rectangle =

\begin{gathered}P = 2(l + w)\\P = 2(35 + 20) = 110\end{gathered}

P=2(l+w)

P=2(35+20)=110

where l is he length and w is the width.

Now,

Perimeter of rectangle = Circumference of ring

Circumference of circle = \pi dπd

where d is the diameter of ring

Equating values, we get,

\begin{gathered}\pi d = 110\\\\\dfrac{22}{7}\times d =110\\\\d = \dfrac{110\times 7}{22} = 35\end{gathered}

πd=110

7

22

y

×d=110

d=

22

110×7

=35

The diameter of ring is 35 cm

Answer 2

Given:

• Length of rectangle = 35 cm
• Width of rectangle = 20 cm

To find:

• Diameter

Solution:

$\sf \red{Perimeter of rectangle }=P = 2(l + w)\\ \\ \sf P = 2(35 + 20) \\ \\ \sf \: P = 110$

Perimeter of rectangle = Circumference of ring

$\sf \purple{Circumference \: of \: circle }= πd$

${\sf {\begin{gathered}\pi d = 110\\\\\dfrac{22}{7}\times d =110\\\\d = \dfrac{110\times 7}{22} = 35\end{gathered} }}$

The diameter of ring is 35 cm.

$\bold\blue{Celestial}\bold\green{Centrix}$