A piece of wire is bent in the shape of a circle of radius 56cm.It is
bent again to form a square. What is the area of the square ?
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Step-by-step explanation:
Given that:- Radius of circle=56cm.
then, circumference of circle= 2πr
=> 2×22/7×56 =352cm.
now we know that the perimeter of square is equal to the circumference of circle..
perimeter of square=352cm.
=>4×side=352cm
=> side = 352/4 =88cm.
Area of square= (side)^2
=>(88)^2 =7744cm^2.
hence,the required area of square=7744cm^2..
hope this helps you...
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