Math, asked by kesarwanikrishnan40, 4 months ago

. A piece of wire is bent in the shape of a circle of radius 56cm.It is

bent again to form a square. What is the area of the square ? (Take the

value of π =22/7
full explanation​

Answers

Answered by shubham69018
0

Step-by-step explanation:

L = 2*pi*r = 4*side of square

4a = 2*22*56/7 = 16*22

area = a^2 = 88^2

Answered by ProtegoHorribilis
1
r of circle = 56 cm
C of circle = 2 (pi) r
= 2 * 22/7 * 56
= 2 * 22 * 8
= 352 cm

C of circle = P of square
Therefore, P of square = 352 cm

Now P of square = 4s

So,
4s = 352
s = 352/4
= 88

Ar(square) = s^2
= 88^2
= 88 * 88
= 7744 cm^2
Similar questions