A piece of wire is bent in the shape of a rectangle whose length and width are 35 cm and 20 cm respectively . It is opned and rebent to form a cicrular ring . What is the diameter of the ring
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Answered by
3
Perimeter of rectangle=2(l+b)
=2(35+20)
=2*55
=110
perimeter of rectangle will be equal to
Circumference of circle =2π r
110=2*22/7*r
110*7/44=r
=17.5
then diameter will be 17.5*2= 35 cm
=2(35+20)
=2*55
=110
perimeter of rectangle will be equal to
Circumference of circle =2π r
110=2*22/7*r
110*7/44=r
=17.5
then diameter will be 17.5*2= 35 cm
Answered by
8
Length of the rectangle = 35 cm
Breadth of the rectangle = 20 cm
Total length of the wire = Perimeter of the rectangle = 2(l+b)
Perimeter = 2(35+20)
= 2×55
= 110 cm
Total length of the wire = 110 cm
Circumference of the circle formed = 110 cm
2πr = 110 cm
2×22/7×r = 110
r = (110×7)/(2×22)
r = 770/44
r = 17.5 cm
Diameter of the circular ring = 2r
= 2×17.5
Diameter of the circular ring = 35 cm
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