Question

A piece of wire is bent in the shape of a square of side 11 cm. It is rebent to form a circular ring. what is the diameter of the ring?
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Answer 1

Answer:

Step-by-step explanation:

Side of square=11cm

Perimeter of square= 4*side=4*11= 44cm

Perimeter of square=Perimeter of circle(circumference of circle)

44=2πr(where r is the radius)

44=2*22/7*r

(44/2) * (7/22)=r

7cm = r

This, diameter =2*r= 2*7=14cm