Question

a piece of wire is bent in the shape of a square of side 11 cm It is bent to form a circular ring what is the diameter of the Ring

Answer 1

Given

Side of a Square = 11 cm

We can find the perimeter of the square

Perimeter of a square = 4 × side

=> Perimeter = 4 × 11

=> P = 44 cm

Now it is Bent to form circular ring. The perimeter would be same because it's made of the same wire.

=> Circumference of the circle formed = 44

=> Circumference of a circle = 2πr = πd

=> Circumference = πd = 44

=> 22/7 × d = 44

=> d = 44 × 7/22

=> d = 2 × 7

=> d = 14 cm

Hope it helps dear friend ☺️✌️

Answer 2

14cm will be the diameter of circle.
solution
perimeter of
$perimeter \: of \: square = 4 \times 11 = 44 \\ \\ circumference \: of \: circle = perimeter \: \: of \: square \\\pi \: d = 44 \\ d = 44 \div 22 \times 7 \\ = 14 \\ \\ 14cm \: will \: be \: the \: diameter \: of \: the \: circle \\ \\ \\ mark \: it \: as \: brainlist \: answer$