Math, asked by mahatoritik, 10 months ago

A piece of wire is bent in the shape of an equilateral triangle of side 4.4cm. If this wire is rebent to form of a circle, find radius and of the circle

Answers

Answered by yash197911

$\huge\boxed{\mathfrak{\underline{\underline{\red{\star QUESTION}}}}}$

A piece of wire is bent in the shape of an equilateral triangle of side 4.4cm. If this wire is rebent to form of a circle, find radius of the circle.

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$\huge\boxed{\mathfrak{\underline{\underline{\blue{\star ANSWER}}}}}$

● GIVEN THAT,

Side of equilateral triangle = 4.4cm.

●AS, P OF EQUILATERAL TRIANGLE = 3×SIDE.

=> P=3×4.4

=> P=13.2 cm

AS, THE SAME WIRE IS REBENT, THE PERIMETER WILL BE SAME.

NOW, PERIMETER OF EQUILATERAL TRIANGLE = CIRCUMFERENCE OF CIRCLE.

=> 13.2 cm = 2 × ${\pi}$ × r.

=> 13.2 cm = ${\frac{44r}{7}}$ .

=> 44r = 13.2 × 7.

=> 44r = 92.4 cm.

$\boxed{\green{\therefore r={\frac{92.4}{44}}= 2.1 cm}}$

$\large{\orange{\mathcal{Final\:Answer: Radius\:Of\:Circle=2.1cm}}}$

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