a piece of wire is bent in the shape of an equilateral triangle of each side 13.2 cm. It is rebent to form a circle ring. what is the diameter of the Ring?
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1
Answer:
The diameter of the circle formed is 12.61
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5
Answer:
The wire is bent in the shape of equilateral triangle, then its perimeter = 3 × 13.2
= 39.6
Since the wire is rebent from the triangle
the perimeter of triangle should be equal to the perimeter of circle.
2Πr = 39.6
Π r = 198/10
r = 198 / 10Π
r = 6.3
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