Question

a piece of wire is bent in the shape of an equilateral triangle of each side 6.6 cm. It is rebent to form a circular ring. what is the diameter of a ring?

Answer 1

perimeter of equilateral triangle(P) = 3a
a=Lt. of side=6.6 cm
=> P= 19.8 cm
Now,
P = circumference of circular ring
P =2πR
19.8 =2×3.14×R
R=3.15 cm
diameter=2R=6.3 cm

Answer 2

Answer:

The diameter of the ring is 6.30 cm.

Step-by-step explanation:

Given : A piece of wire is bent in the shape of an equilateral triangle of each side 6.6 cm. It is re bent to form a circular ring.

To find : What is the diameter of a ring?

Solution :

Side of an equilateral triangle is 6.6 cm.

The perimeter of the equilateral triangle is

$P=3a$

$P=3\times 6.6$

$P=19.8cm$

Now, It is re bent to form a circular ring.

The perimeter of the equilateral triangle is equal to the circumference of the ring.

The circumference of the ring is $C=2\pi r$

So, $19.8=2\pi r$

$19.8=2\times 3.14\times r$

$r=\frac{19.8}{2\times 3.14}$

$r=3.15$

The diameter of the ring is twice the radius.

D=2r=2(3.15)=6.30 cm.

Therefore, The diameter of the ring is 6.30 cm.