a piece of wire is bent in the shape of an equilateral triangle of each side 6.6cm . it is rebent to form a circular ring .what is the diameter of the ring?
Answers
Answer:
each side = 6.6cm
no. of sides =3
therefore perimeter of triangle =6.6×3= 19.8 cm.
when the wire is bent to a circular ring, perimeter i.e., circumference of the circle will be still 19.8 cm.
Therefore,
2πr= 19.8
=>2r=19.8/π
since diameter os equal to twice the radius of the circle, we can say that diameter=19.6/π
=19.8×7/22
=6.3 cm
Hence the diameter of the circle is 6.3 cm.
Hope this answer helps you.
Thanks for asking the question.
Answer :
›»› The diameter of the circular ring are 6.3 cm.
Given :
- A piece of wire is bent in the shape of an equilateral triangle of each side 6.6cm. It is rebent to form a circular ring.
To Find :
- The diameter of the ring = ?
Solution :
→ Perimeter of equilateral traingle = 3a
→ Perimeter of equilateral traingle = 3 * 6.6
→ Perimeter of equilateral traingle = 19.8
Now, it is rebent to form a circular ring.
So, the perimeter of equilateral traingle is equal to the circumference of circular ring.
→ Perimeter = Circumference of circular ring
→ 19.8 = 2πr
→ 19.8 = 2 * 22/7 * r
→ 19.8 = 44/7 * r
→ 19.8 = 6.28 * r
→ r = 19.8/6.28
→ r = 3.15 cm
Now,
→ Diameter = 2r
→ Diameter = 2 * 3.15
→ Diameter = 6.3 cm
║Hence, the diameter of the circular ring are 6.3 cm.║