Question

a piece of wire is bent in the shape of an equilateral triangle of side 8.8 cm It is we went to form a circular ring what is the diameter of the Ring

Answer 1

Bro put perimeter of equalateral triangle equal to perimeter of circle

Answer 2

here => perimeter of the triangle =>
=> 8.8+8.8+8.8=> 26.4 cm
now similarly perimeter of the circular ring =>
=> 2*22/7*r= 26.4
=> radius => 26.4*1/2*7/22 => 4.2 cm
therefore diameter => 4.2+4.2=>8.4 cm