A piece of wire is bent in the shape of an equilateral triangle each of sides 44 cm .If it is re-bent to form a circular ring, what is the diameter of the ring so formed
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Answer:
Length of wire = perimeter of △
=3×4.4⇒13.2cm
Now, the circumference of circle = length of wire
2πr=13.2
r=
2×π
13.2
r=2.1cm
Area of circle ⇒πr
2
⇒π×(2.1)
2
⇒13.86cm
2
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