A piece of wire is bent in the shape of an equilateral triangle each of whose sides measures 8.8 cm.This wire
is rebent to form a circular ring.What is the diameter of the ring?
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side of eq. triangle = 8.8 cm
perimeter of triangle = 3*8.8 = 26.4 cm
perimeter of triangle = perimeter of circle
26.4 = 2πr
r = 26.4/ 6.28
r = 4.20 cm
Hope it helped you
perimeter of triangle = 3*8.8 = 26.4 cm
perimeter of triangle = perimeter of circle
26.4 = 2πr
r = 26.4/ 6.28
r = 4.20 cm
Hope it helped you
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