a piece of wire is bent in the shape of an equilateral triangle each of whose side measure 8.8 CM the wire is bent to form a circular ring what is the diameter of the Ring
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Answered by
0
8.8*3= 26.4cm is diameter
jogendar:
ans is 8.4 cm
Answered by
8
since overall length of wire won't change
so perimeter of triangle = perimeter of Circle
3×8.8= pi×diameter
=(3×8.8)pi
=8.4076433121
~8.4cm
so perimeter of triangle = perimeter of Circle
3×8.8= pi×diameter
=(3×8.8)pi
=8.4076433121
~8.4cm
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