Question

A piece of wire is bent in the shape of an equilateral triangle each of whose side measures 8.8 CM.
this wire is bent to form a circular ring what is the diameter of the Ring

Answer 1

total measure of piece of wire=circumference
of circle
3×8.8 = 2×22÷7×R
26.4 =44÷7×R
26.4×7÷44 =R
4.2 =R

R=4.2

diameter of the circle=2×R
=2×4.2
=8.4

Answer 2

Answer: I Here are your question solution

By Vaishnav Kumar Rajput

Look here

A piece of wire is bent in the shape of an equilateral triangle

Whose side measure=8.8.cm

This wire is bent to a circular ring

So=8.8×3=26.4cm

Now their radius =26.4×7÷22×2

Radius=4.2

And thier diameter =4.2×2=8.4cm...

Hope I help you....

Step-by-step explanation: