a piece of wire is bent in the shape of equilateral triangle of each sides 6.6 cm It is bent to form a circular ring what is the diameter of the Ring
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Side of triangle = 6.6cm
Perimeter of triangle = 6.6 × 3 = 19.8cm
Perimeter of triangle = Circumference of the circle made. (Length of wire same)
19.8 = 2π×r
9.9=3.14×r
r= 3.15
therefore diameter = 2r = 6.3cm
Perimeter of triangle = 6.6 × 3 = 19.8cm
Perimeter of triangle = Circumference of the circle made. (Length of wire same)
19.8 = 2π×r
9.9=3.14×r
r= 3.15
therefore diameter = 2r = 6.3cm
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The diameter of the ring is 6.3 cm
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