Math, asked by bkp1234, 3 months ago

a piece of wire is bent in the shape of equilateral triangle of side 4.4cm. If this wire is rebent to form of a circle , find the radius and the area of the circle. pls say how you found the radius

Answers

Answered by SuitableBoy
16

{\huge{\underline{\underline{\rm{Question:-}}}}}

A Piece of wire is bent in the shape of equilateral triangle of side 4.4 cm . If this wire is re bent to form of a circle . Find the radius and the area of the circle .

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{\huge{\underline{\underline{\rm{Answer\checkmark}}}}}

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Given :

  • The wire is same in both cases.
  • Side of equilateral ∆ = 4.4 cm .
  • It's re bent and made a circle .

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To Prove :

  • Radius of the circle
  • Area of the circle

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Solution :

Since , the wire is same , so , the length of the wire would be same .

# Finding the perimeter of equilateral triangle .

 \mapsto \rm \: perimeter \: of \: equilateral \triangle = 3 \times side

 \mapsto \rm \: perimeter = 3 \times 4.4 \: cm

 \leadsto  \boxed{\rm \: perimeter = 13.2 \: cm \: }

As , the length of the wire is same ,

so ,

 \mapsto \rm \: perimeter \: of \:  \triangle = circumference

 \mapsto \rm \: 13.2 \: cm = 2 \pi \: r

 \mapsto \rm \:  \cancel{13.2} \: cm = 2  \times  \frac{ \cancel{22}}{7}  \times r \\

 \mapsto \rm \:  \cancel{0.6} \: cm \:  =  \cancel2 \times  \frac{r}{7}  \\

 \mapsto \rm \: 0.3 \: cm \times 7 = r

  \leadsto   \pink{\boxed{\rm \: r = 2.1 \: cm}}

Now , finding area .

 \mapsto \rm \: area =  \pi {r}^{2}

 \mapsto \rm \: area =  \frac{22}{7}  \times  {(2.1)}^{2}  \:  {cm}^{2}  \\

 \mapsto \rm \: area =  \frac{22}{ \cancel7}  \times  \cancel{2.1} \times 2.1  \:  {cm}^{2} \\

 \mapsto \rm \: area = 22 \times 0.3 \times 2.1 \:  {cm}^{2}

 \leadsto \purple{ \boxed{ \rm \: area = 13.86 \:  {cm}^{2} \:  }}

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So ,

Final answer :

  • Radius of circle = 2.1 cm
  • Area of circle = 13.86 cm²

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Know More :

# The unit of area is always in the type : unit²

# Perimeter of circle = 2πr

# Area of circle = πr²

# Perimeter of any triangle = sum of all sides

# Area of any triangle = \dfrac{1}{2} × base × height

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