Question

A piece of wire is bent into an equilateral triangle of side 6.6 cm the wire is then bent into a circle what is the radius of the circle

Answer 1

The length of the wire = 3 * 6.6 = 19.8cm
Circumference of the circle
$2\pi r$
Therefore,
19.8 = 2 * 22/7 * r
19.8*7/22*2 = r
0.9*7/2 = r
6.3/2 = r
3.15 cm = r