A piece of wire is bent into an equilateral triangle with each side 11 cm. If the same wire is bent in the form of a circle, find it’s area.
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area of circle is 363 cm^2
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All sides of equilateral triangle=11cm
Perimeter=11+11+11=33cm
Perimeter of triangle=Perimeter of circle
33cm=33cm
perimeter(circumference)of circle=2πr
33=2×22/7×r
33=44r/7
33×7/44=r
231/44=r
r=5.25cm
Area of circle=πr^2
=22/7×(5.25)^2
=22/7×27.56
606.32/7
=86.61714cm^2.
Perimeter=11+11+11=33cm
Perimeter of triangle=Perimeter of circle
33cm=33cm
perimeter(circumference)of circle=2πr
33=2×22/7×r
33=44r/7
33×7/44=r
231/44=r
r=5.25cm
Area of circle=πr^2
=22/7×(5.25)^2
=22/7×27.56
606.32/7
=86.61714cm^2.
Ayushk241:
Thanks for giving my answer a brainliest answer
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