Question

a piece of wire is bent on the shape of an equilateral triangle of each side 6.6 cm . it is rebent to form a circular ring .what is the diameter of the ring{hint:perimeter of triangle =circumfrence of circular ring ,i.e.,π×d=3×6.6

Answer 1

π×d=3×6.6
d=3×6.6×7/22
d=6.3
r=3.15

Answer 2

$\pi \: d \: = 19.8 \\ d = 19.8 \times 7 \div 22 = 6.3$
hope it helps...please mark my answer as brainliest