a piece of wire is bent so as to form the boundary of a square with area a. if the wire is then bent into the shape of an equilateral triangle, what will be the area of the triangle thus bounded in terms of a?
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Area of square = side square = a Let's side = s Perimeter of square = 4s= 4√a = length of wire Side of equilateral triangle is.( 4/3)a = 4a/3 Formula of area of equilateral triangle is (√3/4)b square where b = side of equilateral triangle {(√3*4)/(3*4) } a 4 cancel 4 (√3/3) a 3=√3*√3 (√3/√3*√3)a √3 cancels √3 (1/√3) a a/√3 Therefore answer of area of equilateral triangle in respect to a is = a/√3 Please please please mark as brainliest
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