A piece of wire is in the form of a rectangle whose length and breadth are 40 cm and 26 cm
respectively. It is bent in the form of a circle. Find the radius of the cirle. Also find the area of the
circle and the rectangle. Which figure encloses more area and by how much?
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Given : A piece of wire is in the form of rectangle whose length and breadth are 40 cm and 26 cm respectively it is bent in the form of a circle. To find : The radius of the circle? Therefore, The radius of the circle is 21 cm.
full explanation .
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When wire is in the form of rectangle-
Length of rectangle (l)=40cm
Breadth of rectangle (b)=26cm
Perimeter of rectangle =2(l+b)
⇒ Perimeter of rectangle =2(40+26)=132cm
Area enclosed by the rectangle (A 1 )=l×b
⇒A 1
=40×26=1040cm 2
When the wire is in the form of circle-
Perimeter of circle will be equal to perimeter of rectangle.
∴ Perimeter of circle =132 cm
⇒2πr=132
⇒r= 2
132 × 227
=21cm
Thus the radius of circle is $421 \; cm$$
Now,
Area enclosed by the circle (A 2 )=πr 2
⇒A 2 = 722
×(21) 2 =1386cm 2
∵A 2>A 1
∴A 2 −A 1
=1386−1040=346cm 2
Hence the circle encloses more area than rectangle by 346cm 2
∴A2−A1=1386−1040=346cm2
Hence the circle encloses more area than rectangle by 346cm2.
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